[java] JFrame에서 호출 된 외부 JPanel

이 간단한 작업을 위해 패널을 다른 클래스로 분할 할 필요가 없습니다. 모든 것을 함께 유지하십시오.

package panel;

import java.awt.Color;
import java.awt.event.ActionEvent;
import java.awt.event.ActionListener;
import javax.swing.JButton;
import javax.swing.JFrame;
import javax.swing.JPanel;

public class Frame implements ActionListener {

public JPanel bg,panel1,panel2;
public static JButton btn1, btn2;

public Frame(){

JFrame f = new JFrame();
f.setSize(308, 205);
f.setLayout(null);
f.setLocationRelativeTo(null);
f.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
f.setVisible(true);

bg = new JPanel();
bg.setSize(300, 200);
bg.setLocation(0, 0);
bg.setLayout(null);
bg.setBackground(Color.black);
bg.setVisible(true);

btn1 = new JButton("open 1");
btn1.setSize(135, 30);
btn1.setLocation(10, 10);
btn1.addActionListener(this);

btn2 = new JButton("open 2");
btn2.setSize(135, 30);
btn2.setLocation(155, 10);
btn2.addActionListener(this);

bg.add(btn1);
bg.add(btn2);
f.add(bg);  

panel1 = new JPanel();
panel1.setSize(280, 110);
panel1.setLocation(155, 10);
panel1.setBackground(Color.red);
panel1.setVisible(false);
bg.add(panel1);

panel2 = new JPanel();
panel2.setSize(280, 110);
panel2.setLocation(155, 10);
panel2.setBackground(Color.blue);
panel2.setVisible(false);
bg.add(panel2);



}

public static void main(String[] args) {
new Frame();
}



@Override
public void actionPerformed(ActionEvent a) {

if (a.getSource() == btn1){
panel1.setVisible(true);panel2.setVisible(false);
}
if (a.getSource() == btn2){
panel1.setVisible(false);panel2.setVisible(true);
}
}
}

출처
https://stackoverflow.com/questions/22080104